(3x-4/x^2)=(3/2x)

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Solution for (3x-4/x^2)=(3/2x) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(4/(x^2)) = (3/2)*x // - (3/2)*x

3*x-((3/2)*x)-(4/(x^2)) = 0

3*x+(-3/2)*x-4*x^-2 = 0

3/2*x-4*x^-2 = 0

x*(3/2-4*x^-3) = 0

-4*x^-3 = -3/2 // : -4

x^-3 = 3/8

-3 < 0

1/(x^3) = 3/8 // * x^3

1 = 3/8*x^3 // : 3/8

8/3 = x^3

x^3 = 8/3 // ^ 1/3

x = (8/3)^(1/3)

x = 0

x = 0

x in { 0} 

x = (8/3)^(1/3)

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